Question 1033054
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Let *[tex \Large x] represent the measure of the base.  Then *[tex \Large x\ -\ 10] must represent the measure of the height, and, according to Pythagoras:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  50^2\ =\ x^2\ +\ (x\ -\ 10)^2]


Simplify and then solve the factorable quadratic for the positive root.  Then calculate *[tex \Large x\ -\ 10]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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