Question 1033010
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You have 33 quarters and dimes in a jar. The jar contains a total of $4.95. Write and solve a system of equations 
to find the number x of dimes and the number y of quarters
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Another solution is like this:

Let d be the number of dimes.
Then the number of quarters is (33-d).

The dimes contribute 10*d cents into the total.
The quarters contribute 25*(33-d).

Altogether, the quarter and dimes comprise 495 cents, which gives you an equation

10*d + 25*(33-d) = 495.

Simplify and solve for d:

10d + 825 - 25d = 495,   or

-15d = 495-825,

-15d = -330,

d = {{{(-330)/(-15)}}} = 22.

So, there are 22 dimes.

Then the number of quarters is 33 - 22 = 11.

<U>Check</U>.  22*10 + 11*25 = 495.   OK!

<U>Answer</U>.  22 dimes and 11 quarters.
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