Question 1032959
 Use the given information to determine the exact trigonometric value.
sec(theta)=-7/5, 90 < theta < 180 ;
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sec = r/x, so r = 7 and x = -5
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Since theta is in QII, y is positive::
y = sqrt[7^2 - 5^2] = sqrt(24) = 2sqrt(6)
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Ans:: sin(theta) = y/r = 2sqrt(6)/7
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Cheers,
Stan H.
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