Question 1032930
Michael is running for president. The proportion of voters who favor him is 0.3. A simple random sample of 100 voters is taken.
 What is the expected value :: n*p = 100*0.3 = 30 
standard deviation:: sqrt(n*p*q) = sqrt(30*0.7) = 4.58 
and shape of the sampling distribution of p?:: binomial distribution
-------------------------
 What is the probability that the number of voters who will favor Michael in the sample will be between 36 and 40?
P(36<= x <= 40) = binomcdf(100,0.3,40)-binomcdf(100,0.3,35) = 0.1036
 What is the probability that the number of voters who will favor Michael in the sample will be more than 26?:: 
P(27<= x <= 40) = 1 - P(0<= x <= 26) = 1 - binomcdf(100,0.3,26) = 0.7756
-----------------
Comment:: Modified answer to Part 3 as requested.
---------------------
Cheers,
Stan H.
----------