Question 1032890
 ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to reach its maximum height ? What is the balls maximum height ? Round to the nearest hundredth of necessary 
------
Max occurs when t = -b/(2a) = -48/(2*-16) = 3/2 seconds
---------------------------
Max height = h(3/2)
-----------------------
Cheers,
Stan H.
------------