Question 89066


     solve:

(x+2)^2=12

            (x+2)^2 = 12
             x^2+4x+4-12 = 0
              x^2+4x-8  = 0
           use the formula   x = -b+-sq rt b^2-4ac/2a
           where a =1  b = 4  c= -8

       substitute  the values of a,b&c

              x = -4+-sq rt 4^2-4.1.(-8)/2.1

                = -4+-sq rt 16+32/2
                = -4+sq rt 48/2
                = -4+-4sq rt3/2
                = 2(-2+-sq rt3)/2
                = -2+-sq rt3