Question 1032781
let the first number be a.
let the second number be b.


a = 2b + 1
ab = 10


in the second equation, replace a with 2b + 1 to get:


(2b + 1) * b = 10


simplify to get 2b^2 + b = 10


subtract 10 from both sides of the equation to get 2b^2 + b - 10 = 0


factor the quadratic equation to get (b - 2) * (2b + 5) = 0


solve for b to get b = 2 or b = -5/2


since a = 2b + 1, you get a = 5 which b = 2, and you get a = -4 when b = -5/2.


when a = 5 and b = 2, ab = 10 becomes 5*2 = 10 which becomes 10 = 10.


when a = -4 and b = -5/2, you get ab = 10 becomes -4 * -2.5 = 10 which becomes 10 = 10.


the value look good.


your solutions are:


a = 5 when b = 2


a = -4 when b = -5/2