Question 1032761
*[illustration same]
Area of BPQ =8

BQ = 4

there fore PM altitude = 

8= 1/2 *4* PM

PM = 4

The altitude of BPC = PM = 4

Area of triangle BPC = 1/2 * 4* 10

= 20 sq units

Area OF PQC = Area BPC - BPQ = 12 sq units


Now PQ || AC  and AC is common side

triangles AQC & PQC are congruent


Areas are equal 12 sq units