Question 1032664
a. The amount of force {{{F}}}  that the tractor can exert is applied to the stump.
b. How close is that nearby pole, how tight is the rope, and how is it tied?
I envision something like this:
{{{drawing(1100,300,-5.5,5.5,-0.5,2.5,
red(arrow(0,1,0,2)),green(triangle(-5,0,5,0,0,1)),
locate(2.3,0.2,green(5ft)),locate(-2.7,0.2,green(5ft)),
locate(0.02,0.6,green(1ft)),green(triangle(-2.5,0.5,-2.55,0.55,-2.45,0.55)),
locate(-2.8,0.85,green(0.5F)),
green(triangle(-5,0,0,0,0,1)),green(rectangle(0,0,0.1,0.1)),
green(triangle(0,1,-2.5,1,-2.5,0.5)),locate(-2.4,1.2,green(2.5F)),
blue(arrow(0,1,2.5,0.5)),blue(arrow(0,1,-2.5,0.5)),
locate(0.1,2.05,F),locate(-2.2,0.55,R),
green(arrow(0,1,-2.5,1)),green(arrow(-2.5,1,-2.5,0.5)),
locate(2.5,0.7,R),circle(-5,0,0.08),circle(5,0,0.08),
locate(-5.2,-0.1,stump),locate(5,-0.1,pole)
)}}} The forces shown are the forward pull of the tractor (F), and the reaction forces of the stump and the pole, jointly pulling the tractor backwards.
The rope is a physics-problem rope that has no mass, and transmits 100% of the force applied, without stretching.
As neither one (tractor, pole or stump) is moving, the net force on the middle of the rope is zero.
The forward component of each force is
F for the tractor pull,
-0.5F for the reaction of the stump,
-0.5F for the reaction of the pole,
0.5F for the forwards pulling action on the stump, and
0.5F for the forwards pulling action on the pole.
The rightwards components of the forces are
0 for the pull of the tractor because it is pulling straight ahead,
-2.5F for the reaction of the stump pulling the tractor to the left,
2.5F for the reaction of the pole pulling the tractor to the right (cancelling the leftwards pull from the stump),
2.5F for the rightwards action pull on the stump, and
-2.5 for the leftwards action pull on the pole.
The 2.5F to 0.5F ratio of sideways to backwards R force component magnitudes is the same as the ratio of the 5ft and 1ft corresponding sides of the similar green triangle.