Question 1032628
Let z = 4(cos 3π/2 + i sin 3π/2) and w = 3(cos π/6 + i sin π/6). Write the rectangular form of z/w.
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z = 4cis(3pi/2), w = 3cis(pi/6)
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z/w = (4/3)cis(3pi/2 - pi/6) = (4/3)cis(4pi/3)
z/w = (4/3)*cos(4pi/3) + (4i/3)*sin(4pi/3)
z/w = (4/3)*(-1/2) + (4i/3)*(-sqrt(3)/2)
z/w = -2/3 - i*2sqrt(3)/3
= (2/3)*(-1 - sqrt(3)i)
--> same answer as Stanbon