Question 1032580
If we call the rate of the slower train r, than the faster one travels at r+7.
We also know that rate times time = distance, or rt = d.
The time they travel is two hours.  We then write
2r + 2(r+7) = 250
2r + 2r + 14 = 250
4r + 14 = 250
4r = 236
r = 59 mph so that the faster train travels at
r+7 = 66 mph