Question 1032530
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Pls help me solve this. this is the last equation for my homework.


Robert has 35 coins consisting dimes and quarters. If the total value is $5.90, how many of each kind of coin are there?
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Or this another solution.


<pre>
Let d be the number of dimes.
Then the number of quarters is 35-d.

The dimes contribute 10*d cents to the total. 
The quarters contribute 25*(35-d) cents to the total.

As a result, the total is 10*d + 25*(35-d).
Since the total is 590 cents, it gives you an equation

10*d + 25*(35-d) = 590.

Simplify and solve it for d:

10d + 875 - 25d = 590,

10d - 25d = 590 -875,

-15d = -285,

d = {{{(-285)/(-15)}}} = 19.

So, there are 19 dimes.
Then the number of quarters is 35-19 = 16.

<U>Answer</U>. 19 dimes and 16 quarters.
</pre>