Question 1032530
Robert has 35 coins consisting dimes and quarters. 
d + q = 35 coins
---------------
If the total value is $5.90, how many of each kind of coin are there?
10d + 25q = 590 cents
-----
Modify for elimination::
d + q = 35
d + 2.5q = 59
---------
Subtract and solve for "q":
1.5q = 24
----
q = 16 (# of quarters)
d = 35-16 = 19 (# of dimes)
------------
Cheers,
Stan H.
------------