Question 1032070
 Log2(2x+1) = log2 (x+2) - log2 (3)
-------------
log2(2x+1) = log2[(x+2)/3]
------
2x+1 = (x+2)/3
----
6x+3 = x+2
5x = -1
x = -1/5
---------------
Cheers,
Stan H.
---------------