Question 1032480
{{{y=Ie^(kt)}}}, changed y sub 0  to I for easier typing of text;


{{{ln(Ie^(kt))=ln(y)}}}
{{{ln(I)+kt*ln(e)=ln(y)}}}
{{{kt*1=ln(y)-ln(I)}}}
{{{highlight(k=(1/t)(ln(y/I)))}}}


Substitute the given values and evaluate.