Question 1032273
Separate the variables,
{{{dy/y=(x/3)dx}}}
{{{ln(y)=(1/6)x^2+C}}}
{{{y=Ce^((1/6)x^2))}}}
When {{{x=0}}},{{{y=4}}},
{{{C=4}}}
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{{{y=4e^(x^2/6))}}}

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The exponent is {{{x^2/6}}}.