Question 1032352
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The freight train gets a 72-mile head start because it left three hours before the passenger train going 24 miles per hour.


In order for the two trains to pass, the freight train is going to travel some distance *[tex \Large d] in some amount of time *[tex \Large t] going 24 mph, which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ 24t]


And the passenger train has to go that same distance plus the 72-mile head start going 60 mph, in other words:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ +\ 72\ =\ 60t]


Solve the 2X2 system for *[tex \Large d]. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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