Question 1032349
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If *[tex \Large x] is an odd integer, then the next consecutive odd integer is *[tex \Large x\ +\ 2].  The product of the two is *[tex \Large x^2\ +\ 2x].  You are given that this product is equal to 783.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 2x\ =\ 783]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 2x\ -\ 783\ =\ 0]


Solve the factorable quadratic.  The positive value of *[tex \Large x] is the younger guy's age.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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