Question 1032302
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4x^2 + 3y^2 =  4,    (1)
2x   - 2y^2 = -3.    (2)

From (2), express 2x = {{{-3 + 2y^2}}}. Now, substitute it into (1) by noting that {{{4x^2}}} = {{{(2x)^2}}}. You will get a single equation for {{{y^2}}}:

{{{(-3+2y^2)^2}}} + {{{3y^2}}} = 4.

Open parentheses, collect the like terms and introduce the new variable z = {{{y^2}}}.

Solve the obtained quadratic equation for z.

Then find "y" from z = {{{y^2}}}.

Then find "x" from (2).
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