Question 1032299
{{{5 tan (theta) = 12 }}} 

{{{tan (theta) = 12/5 }}} 

{{{tan^2 (theta) = 144/25 }}} 



{{{1+tan^2 (theta) = 1 + (144/25)}}} 

{{{sec^2(theta)= 169/25}}}


{{{sec(theta)}}} =+/-(13/5)

{{{cos (theta) }}}=+/- (5/13)