Question 1032255
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Solve the equation. 

   4cos^2(x)-3=0
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<pre>
{{{4cos^2(x) - 3}}} = {{{0}}}  --->

{{{cos^2(x)}}} = {{{3/4}}}  --->

{{{cos(x)}}} = +/- {{{sqrt(3)/2}}},

x = {{{pi/6}}}, {{{5pi/6}}}, {{{7pi/6}}}, {{{11pi/6}}} in the interval [{{{0}}}, {{{2pi}}}).
</pre>