Question 1032244
1:


Use polynomial division  (unless you know synthetic division for that kind of divisor).  The quotient will be quadratic, and you can then either factor it or use general solution for quadratic formula to get the roots.



2:


{{{3x^2-8x+k=0}}}
If you want complex solutions with imaginary parts, then use discriminant related to less than 0.
-
{{{(-8)^2-4*3*k<0}}}
Solve this statement for k.
{{{-12k+64<0}}}
{{{-12k<-64}}}
{{{k>64/12}}}
{{{k>32/6}}}
{{{highlight(k>16/3)}}}