Question 1032221
The sum of three integers is 353. The sum of the first and second integers exceeds the third by 63. The third integer is 51 less than the first. Find the three integers. 
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a + b + c = 353
a+b = c + 63
c = a-51
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Modify to get one variable::
c = a-51
b = -a + (a-51) + 63 = 12
a = a
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Substitute and solve for "a"::
a + 12 + a-51 = 353
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2a - 39 = 353
2a = 392
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a = 196
b = 12
c = 196-51 = 145
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Cheers,
Stan H.
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