<PRE><B>Question 1032221</B>
Hi there,
The sum of three integers is 353.
x + y + z = 353........(1)
The sum of the first and second 
integers exceeds the third by 63.  
x + y = z + 63
Reorganize
x + y - z = 63.........(2)
The third integer is 51 less than 
the first.
z = x - 51.............(3)
...................
Using Equations(1)and(2)
x + y + z = 353.....(1)
x + y - z = 63......(2)
Add
2x + 2y = 416......(4)
...........
Using Equation (3)
z = x - 51
substitute (x - 51) for z
in Equation (1)
x + y + z = 353.......(1)
x + y + (x - 51) = 353
x + y + x = 353 + 51
2x + y = 404.....(5)
Using Equations (4) and (5)
2x + 2y = 416 .....(4)
2x + y = 404.......(5)
Subtract:
y = 12.
Substitute y = 12 into
Equation (4)
2x + 2y = 416....(4)
2x +2(12) = 416
2x + 24 = 416
2x = 416 - 24
2x = 392
x = 196
Substitute y = 12 and
x = 196 into Equation (1)
x + y + z = 353.....(1)
196 + 12 + z = 353
z = 353 - 208
z = 145
x = 196, y = 12 and z = 145.
Hope this helps :-)</PRE>