Question 1032132
Let {{{3x^2 - 20x +3p + 4  = 0}}}.

==> {{{x^2 - (20/3)x + (3p + 4)/3  = 0}}}.

Now if one root is a, then by hypothesis, the other root is 4a.

==> {{{-(a+4a) = -20/3}}},  and {{{a(4a) = 4a^2 = (3p + 4)/3}}}.

==> {{{a = 4/3}}}, and {{{4(16/9) = (3p + 4)/3}}}.

==> {{{64/9 = (3p + 4)/3}}}.  ==> {{{p = 52/9}}}