Question 1032113
Jane and Jill live 13.5 km apart.

d=13.5 km

The ratio of Jane's speed to Jill's is 5:4. 
let common multiple be x
Jane's speed =5x
Jill's speed =4x. 

 At 10:00 AM each girl leaves her house and jogs toward the other. If the girls meet at 11:15 AM,

time = 1 1/4 hour  => 5/4


time = 13.5/(5x+4x)

5/4 = 13.5/9x

45x = 54

x= 6/5

5x = 5*6/5 = 6 km/h=> jane

distance = 6*1.25 = 7.50 km

4x = 4*6/5 = 4.8 km/h => Jill
distance = 1,25*4.8 =6  km






 how fast does each jog? Give Rate, Time, and distance for each girl.