Question 1032091
 The product of two consecutive positive even integers is 14 more than their sum.
let x & (x+2) = the two consecutive positive even integers
then
x(x+2) = x + (x+2) + 14
x^2 + 2x = 2x + 16
:
 Set up an equation that can be used to find the two numbers and solve it.
Form a quadratic equation on the left
x^2 + 2x - 2x - 16 = 0
x^2 - 16 = 0
Can be factored as the difference of squares
(x-4)(x+4) = 0
The positive solution
x = 4; the next integer is 6
:
:
Check this in the original statement
" The product of two consecutive positive even intergers is 14 more than their sum. "
4 * 6 = 4 + 6 + 14
24 = 10 + 14