Question 1032005
A (n)=0.5*3^(n-1); I am assuming n-1 is the exponent.
I would substitute the number for n
A(1)=0.5*3^(1-1)=0.5*3^0; 3^0=1, so A(1)=0.5
A(4)=0.5*3^(4-1)=0.5*3^3; 3^3=27, and 27*(0.5)=13.5
A(8)=0.5*3^(8-1)=0.5*3^7;3^7=2187. and 2187*0.5=1093.5