Question 1031989


a=	-3	,	b=	-5		c=	2	
								
b^2-4ac=	25	+	24					
b^2-4ac=	49							
{{{	sqrt(	49	)=	7	}}}			
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	5	+	7	)/	-6			
x1=	-2.00							
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}								
x2=(	5	-7	) /	-6				
x2=	0.33							


-2, 0.33