<PRE><B>Question 88965</B>
A rectangle has sides of 5x-12 and 5x+12. 
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What is the area of the rectangle?
(5x-12)(5x+12) = 25x^2-144 sq units
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 Inside the rectangle two squares with sides of x and x are to be removed. What is the remaining area of the rectangle?
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Area of the two squares = x^2 + x^2 = 2x^2
Remaining area = 25x^2-144 -(2x^2)
= 23x^2-144
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Cheers,
Stan H.
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