Question 1031867
Let us rearrange
-2x^2-4x+y+2=0
to get
{{{y = 2x^2 + 4x - 2}}}
Now factor out the two and complete the square...we get...
{{{y = 2(x^2 + 2x - 1)}}}
{{{y = 2(x^2 + 2x + 1) - 4}}}  (look carefully on this part)
{{{y = 2(x + 1)^2 - 4}}}