Question 1031849
 A man is 4 times as old as his daughter was 3 years ago.If their combined ages is 48,how old is the daughter now?
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f = 4(d-3)
f + d = 48
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Substitute for "f" and solve for "d"::
4(d-3) + d = 48
4d - 12 + d = 48
5d = 60
daughter's age = 12 yrs
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Cheers,
Stan H.
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