Question 1031819
The length of a particular rectangle is 8 inches more than 2 times its width.

let width be x

length  will be 2x+8

Area = x(2x+8)

 A new rectangle is formed by tripling the width.

new width = 3x
length = 2x+8

Area = 3x(2x+8)

 The area is 30 square inches more than the area of original rectangle.
3x(2x+8) -x(2x+8)=30

2x(2x+8) = 30

4x^2 +8x -30=0

4x^2+12x-10x-30=0

4x(x+3)-10(x+3)=0

(x+3)(4x-10)=0

x=-3 OR 5/2

Taking positive value  width = 5/2 

Length = 2x+8

=2*5/2 + 8

=13
the dimensions of the original rectangle 2.5 in by 13 in