<PRE><B>Question 1031718</B>
5/(x^2+x-6) = 2 + (x-3)/(x-2)
x^2+x-6 can be factored.
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{{{5/((x+3)*(x-2)) = 2 + (x-3)/(x-2)}}}
LCD = (x+3)*(x-2)
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{{{5/((x+3)*(x-2)) = 2 + (x-3)*(x+3)/LCD}}}
Multiply thru by DEN, the LCD
5 = 2*(x^2+x-6) + (x-3)*(x+3)
5 = 3x^2 + 2x - 21
3x^2 + 2x - 26 = 0
*[invoke solve_quadratic_equation 3,2,-26]
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