Question 1031775
you can't take the log of a negative number or 0, therefore the expression within the log function sign has to be greater than 0.


this means that (x-2)-5 has to be greater than 0.


(x-2)-5 is the same as x-7 so you get x-7 has to be greater than 0.


this means that x has to be greater than 7.


here's the graph of that equation.


<img src = "http://theo.x10hosting.com/2016/042701.jpg" alt="$$$" </>


there is an asymptote at x = 7.


the graph is only valid when x > 7.


this is because you can't take the log of a negative number or 0 and get a real answer that can be graphed on the real plane.


log((x-2)-5) = log(x-7).


x-7 > 0 results in x > 7.


your domain is all real values of x such that x > 7.