Question 88936
2^x = 30 
Take the log of both sides to get:
x(log2) = log30
x = [log30]/[log2]
x = 4.90689..

---------------------

5^(x - 1) = 3^x 
Take the log of both sides
(x-1)log5 = xlog3
xlog5 -xlo3 = log5
x(log5 - log3) = log5
x(0.2218487..) = 0.6987000...
x = 5.15066...
---------------

3.5^(3x + 1) = 65.4 
Take the log of both sides:
(3x+1)log3.5 = log65.4
(3log3.5)x = log65.4
x = 0.329266....
-----------

16^(x - 4) = 3^(3 - x )
Take the log of both sides
(x-4)log16 = (3-x)log3
Can you take it from here?
--------

7^(x - 2) = 5^x
Take the log of both sides
Can you take it from here?
=============
Cheers,
Stan H.