<PRE><B>Question 1031723</B>
speed	x					
speed	x	+	6			
						
Distance = same		432	km   	1		
original time – time with increased speed =					1	hour
t=d/t						

432	/	x	-	432	/	(	x	+	6	)	=	1				
LCD=	x	(	x	+	6	)										
multiply by LCD																
432	(	x	+	6	)	-	432	x	=	1	x	(	x	+	6	)
432	x	+	2592	-	432	x	=	1	X^2	+	6	x				
2592	=		x^2	+	6	x										
	x^2		+	6	x	-	-2592	=	0		
x^2 +6x +9 = 2592+9

(x+3)^2 =2601

(x+3) = +/- {{{2601}}}

x+3 = +/- 51

x= 51-3 = 48 km/h

					
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