Question 1031712
distance = time x rate
rate for car 1 = x
rate for car 2 = x + 30
time for car 1 = 6 hours
time for car 2 = 3 hours (the faster car takes less time)
.
Since distance is the same:
rate car 1 x time car 1 = rate car 2 x time car 2
(x)(6)=(x+30)(3)
6x=3x+90 . Subtract 3x from each side.
3x=90 . Divide each side by 3.
x=30
.
The rate for car 1 is 30 mph. After 6 hours, the car has traveled 180 miles
The rate for car 2 is (30mph+30mph)=60 mph After 3 hours, the car has traveled 180 miles.