Question 1031670
calculate the area under the curve y=f(x)= x^2 ln(x^3) from x=0 to x=1
---------
f(x) = 3x^2*ln(x)
INT(x) = 3*(x^3*ln(x)/3 - x^3/9) --- ignore the constant of integration
INT(1) = 3*1*0/3 - 3*1/9 = -1/3
INT(0) = 0
--> area = 1/3 sq unit, below the x-axis.