Question 1031664
{{{abs(x-1)=x-1}}} when {{{x-1>=0}}} or {{{x>=1}}}
{{{abs(x-1)=-(x-1)=-x+1}}} when {{{x-1<0}}} or {{{x<1}}}
So then,
when {{{x>=1}}}
{{{x^2-(x-1)-3=0}}}
{{{x^2-x+1-3=0}}}
{{{x^2-x-2=0}}}
{{{(x-2)(x+1)=0}}}
Only one factor is in the range,
{{{x-2=0}}}
{{{highlight(x=2)}}}
and when {{{x<1}}}
{{{x^2-(-x+1)-3=0}}}
{{{x^2+x-4=0}}}
{{{(x^2+x+1/4)-4-1/4=0}}}
{{{(x+1/2)^2=17/4}}}
{{{x+1/2=0 +- sqrt(17)/2}}}
{{{x=-1/2 +- sqrt(17)/2}}}
Again only one factor is in the range,
{{{x=-1/2 - sqrt(17)/2}}}
{{{highlight(x=-((1+sqrt(17)))/2)}}}
*[illustration dq12.JPG].