Question 1031659
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Can you help me with some questions to help me understand how to do it?


<pre>
log5 7x=2            7x = {{{5^2}}}

log3(n-3)=4          n-3 = {{{3^4}}}

logx(49)=2           x = 7

log(1000)=x          {{{log(10,(1000))}}} = 3  --->  x = 3.

log2(2^5^X^-1)=9     ambiguous since you don't use parentheses properly

log(4x-1)=2          {{{log(10,(4x-1))}}} = 2  --->  4x-1 = 100.
</pre>