Question 1031517
<pre>
1    |    1    -6    -9    14
     |
     |         1     -5    -14
     |_____________________________________
         1    -5     -14    0</pre>  and notice the remainder is 0.



No need to use synthetic division again unless you really want; because you can  factorize {{{x^2-5x-14}}} just looking for the combination that works.  


{{{f(x)=x^2-5x-14=highlight((x+2)(x-7))}}}.