Question 1031528
<pre>
The number of cans of paint needed is directly 
proportional to the number of stop signs that can
be painted with them:

{{{matrix(1,3,

matrix(1,4,24,cans,of,paint)/matrix(1,3,120,stop,signs),""="",
matrix(1,4,13,cans,of,paint)/matrix(1,3,N,stop,signs))}}}

{{{matrix(1,3,

24/120,""="",13/N)}}}

Cross multiply:

{{{matrix(1,3,

24N,""="",13*120)}}}

{{{matrix(1,3,

N,""="",13*120/24)}}}

{{{matrix(1,3,

N,""="",65)}}} stop signs.

Edwin</pre>