<PRE><B>Question 1031476</B>


Triangle ABC with A(2, 1), B(4, 9) and C(16,1). 



Mid point of AB A(2, 1), B(4, 9)  = (3,5) Slope of AB = 4
The perpendicular at M will have a slope of (-1/4) and passes through (3,5)
5 =(-1/4)*3 +c
5=-3/4 +c
20=-3+4c
23=4c
c= 23/4
The equation is y = (-1/4)x + 23/4

Repeat for BC and CA

Mid point of BC  B(4, 9) and C(16,1).= (10,5)


Mid point of CA  C(16,1)A(2, 1),  .= (9,1)
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