Question 1031478
=(2x-3y)^2 / (3y-2x)^2
=(2x-3y)^2 / [-(2x-3y)]^2
=(2x-3y)^2 / (2x-3y)^2 <----- How do you go from this step to the next step?

Since
Z/Z=1
Why does your final step equal -1?