Question 1031459
<pre>
{{{log((z+5))}}}{{{""=""}}}{{{8}}}

When the base of the logarithm is not written, it is
understood to be 10.  So the given problem is:

{{{log(10,(z+5))}}}{{{""=""}}}{{{8}}}

Learn the principle of equivalent 
logarithm and exponential equations: 

       {{{log(B,A)=C}}} is equivalent to {{{A=B^C}}}

Use that principle to change the logarithm form to the 
exponential:

{{{z+5}}}{{{""=""}}}{{{10^8}}}

{{{z+5}}}{{{""=""}}}{{{100000000}}}

{{{z}}}{{{""=""}}}{{{99999995}}}

Edwin</pre>