Question 1031429

Find two integers such that the first is 2 more than twice the second and their product is 112.

let second number be x
first number => 2x+2

x(2x+2) = 112

3x^2+2x=112
/2
x^2+x=56

x^2+x-56=0

x^2+8x-7x-56=0

x(x+8)-7(x+8)=0

(x+8)(x-7)=0

x=-8 OR x=7

2x+2 when x=-8

=-14

(-8,-14)

2x+2 when x=7

=16

(7,16)