Question 1031156
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  -10\ +\ \log_3\left(n\,+\,3\right)\ =\ -10]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \log_3\left(n\,+\,3\right)\ =\ 0]


The only way for the logarithm function of any base to have a zero value is if the argument of the function is equal to 1.  Check it out with a graphing program that lets you graph logs to any base.  No matter what base you choose, the graph of *[tex \Large \log_b(x)] will cross the x-axis at (1,0).


Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  n\ +\ 3\ =\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  n\ =\ -2]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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