Question 1031151
set x = the first integer
x + 1 = the second integer
x + 2 = the third integer
Below we see squaring the middle then subtracting the product of the other two
(x + 1)^2 - x(x + 2) ?= 1
x^2 + 2x + 1 - ( x^2 + 2x )
x^2 + 2x + 1 - x^2 - 2x
Simplifying we have 1
Does this help?
The above works for any 3 consecutive integers.