Question 1031125
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Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
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After you get 

sin(x) = cos(x),

as the previous tutor got, the continuation is

tan(x) = 1.

Hence, x = {{{pi/4 + 2k*pi}}}  or/and  x = {{{5pi/4 + 2k*pi}}}, k = 0, +/-1, +/- 2, . . . 
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